Ответ:
Применяем свойства степеней [tex]\bf \dfrac{a^{n}}{a^{k}}=\dfrac{a^{n-k}}{1}=\dfrac{1}{a^{k-n}}[/tex] .
[tex]\displaystyle \frac{22\, n\, m^2}{c}\, :\,\frac{33\, n^2m^5}{-c^3}=\frac{22\, n\, m^2}{c}\cdot \frac{-c^3}{33\, n^2m^5}=-\frac{2\, c^2}{3\, n\, m^3}\\\\\\\frac{r}{d^2}\, :\,\frac{4\, r^2}{2\, d}=\frac{r}{d^2}\cdot \frac{2\, d}{4\, r^2}=\frac{1}{2\, r\, d}\\\\\\\frac{39\, n\, m}{6\, z\, k}\, :\, \frac{13\, n\, m^2}{2\, kz^3}=\frac{39\, n\, m}{6\, z\, k}\cdot \frac{2\, k\, z^3}{13\, n\, m^2}=\frac{3\, z^2}{3\, m}=\frac{z^2}{m}[/tex]
