[tex]\displaystyle\bf\\f(x)=3tg\Big(x-\frac{\pi }{8} \Big)+\sqrt{3} \\\\f(x)=0\\\\3tg\Big(x-\frac{\pi }{8} \Big)+\sqrt{3} =0\\\\3tg\Big(x-\frac{\pi }{8} \Big)=-\sqrt{3}\\\\tg\Big(x-\frac{\pi }{8} \Big)=-\frac{\sqrt{3} }{3} \\\\\\ x-\frac{\pi }{8} =arctg\Big(-\frac{\sqrt{3} }{3} \Big)+\pi n,n\in Z\\\\\\ x-\frac{\pi }{8} =-arctg\frac{\sqrt{3} }{3} +\pi n,n\in Z\\\\\\ x-\frac{\pi }{8} =-\frac{\pi }{6} +\pi n,n\in Z\\\\\\\ x=\frac{\pi }{8} -\frac{\pi }{6} +\pi n,n\in Z\\\\\\ x=-\frac{\pi }{24} +\pi n,n\in Z[/tex]
