{3x+y=2
{y^2-x^2=12
{y=2-3x
{(2-3x)^2-x^2=12
4-12x+8x^2=12
8x^2-12x-8=0
D=144+4*8*8=20^2
x1=(12+20)/16=2
x2=(12-20)/16=-1/2
y1=2-6=-4
y2=2+3/2=7/2
Ответ (2,-4) U (-1/2,7/2)
[tex]\left \{ {{3x+y=2} \atop {x^{2}- y^{2}=-12}} \right. \\\\\left \{ {{y=2-3x} \atop {x^{2}-(2-3x)^{2}=-12}} \right.\\\\\left \{ {{y=2-3x} \atop {x^{2}-4+12x-9x^{2}+12=0}} \right.\\\\\left \{ {{y=2-3x} \atop {-8x^{2}+12x+8=0 }} \right.\\\\\left \{ {{y=2-3x} \atop {2x^{2}-3x-2=0 }} \right.[/tex]
[tex]1)\left \{ {{x_{1}=2 } \atop {y_{1}=2-3*2}} \right.\\\\\left \{ {{x_{1}=2 } \atop {y_{1} =-4}} \right. \\\\2)\left \{ {{x_{2}=-0,5 } \atop {y_{2}=2-3*(-0,5) }} \right.\\\\\left \{ {{x_{2}=-0,5 } \atop {y_{2}=3,5 }} \right.\\\\Otvet:(2;-4),(-0,5;3,5)[/tex]
