x²=-4x+32
х²+4х-32=0
Д= 4²-4×1×(-32) = 16 + 128 = 144
х1 = -4 + 12 / 2 = 4
х2 = -4-12 / 2 =-8
[tex] {x}^{2} + 4x - 32 = 0 \\ d = 16 + 128 = 144 \\ x1 = \frac{ - 4 - 12}{2} = - 8 \\ x2 = \frac{ - 4 + 12}{2} = 4 [/tex]
Ответ:-8,4.
