Ответ :

[tex]x^2y^2-16=(xy-4)(xy+4) \\\ 36-a^2b^2=(6-ab)(6+ab) \\\ m^2n^2-0.09=(mn-0.3)(mn+0.3) \\\ \frac{16}{25}-k^2p^2= (\frac{4}{5}-kp)( \frac{4}{5}+kp)[/tex]

[tex]0.81p^2-4a^2b^2=(0.9p-2ab)(0.9p+2ab) \\\ 9m^2n^2-0.01p^2=(3mn-0.1p)(3mn+0.1p) \\\ 0.04k^2-0.09a^2n^2=(0.2k-0.3an)(0.2k+0.3an) \\\ \frac{1}{9}a^2b^2-2 \frac{7}{9}m^2p^2=( \frac{1}{3}ab-\frac{5}{3}mp)( \frac{1}{3}ab++ \frac{5}{3}mp)[/tex]