Решите неравенство:
|1 - X| > 3
[tex]|1-x|>3, \\ \left [ {1-x<-3} \atop {1-x>3;}} \right.}} \right. \ \left [ {{-x<-4} \atop {-x>2}} \right. \ \left [ {x>4,} \atop {x<-2;}} \right. \ \\ x\in(-\infty;-2)\cup(4;+\infty).[/tex]
([1-x])^2>(3)^2
(a+d)^2>9
x^2+2x+8 (по теореме Виета) X1=2, X2=-4
(U:-2)(U:4)
